Posted: January 28th, 2022

The Z-score allows one to estimate the probability of a score

Psychology homework help 300 WORDS:

The Z-score allows one to estimate the probability of a score. This could be needing to know how low or how high to score on an exam to pass or fail. Knowing the mean and the standard deviation will allow one to convert to a z table to know the percentage of a score. Just knowing the mean and score only accommodates one score and average related to all collected data. Knowing your score on an exam and the mean of all other exams will not answer the score desired or needed to pass. If a student was failing and had two more tests coming up, the z-score could be utilized to determine grade needed to pass.

A score at the mean is equal to a z score of 0. A score 1 SD above the mean would be equal to a z score of +1.0. A score 1 below the mean would equal to a z score of -1.0″ (Week3 Lecture 1).

Example: Using information below on charts provided

Rounding to a mean of 85, and SD of 6. The mean of 85 is the middle or 50% out of 100% on a normal distribution bell curve. To get the top 25% you would utilize the mean and SD to convert to a z score. A z score consists of a table with the given criteria. To accommodate the top 25%, you need to get the percentage of at least 75%. On a Z table . 68 is 75.17, which meets the 75% needed. Now one would take that . 68 multiply by SD and add the mean. .68×6+85=89.08. Looking at the information below Crystal and Skylar are in the top 25%.

RESPOND IN 300N WORDS:

One of the primary purposes of a z-score is to describing the exact location of a score within a distribution. The z-score accomplishes this goal by transforming each X value into a signed number (+or-) the sign tells whether the score is located above (+) or below (-) the mean and the number tells the distance between the score and the mean in terms of the number of standard deviations.

When describing how an individual performed on an exam you need the z-score to get more information. If you just have the mean and the value of the score, you still would need the standard deviation to have all the information to get the correct z-score.

Students Test Scores Z-Scores

S1 175 -0.360624459

S2 206 1.831406566

S3 150 -2.128391415

S4 165 -1.067731241

S5 180 -0.007071068

S6 210 2.114249279

S7 200 1.407142497

S8 190 0.700035715

S9 170 -0.71417785

S10 155 -1.774838024

M of Scores 180.1

SD of Scores 14.14213562

When you have the z-score you are getting the standardized score that shows a little more about the average out of the ten students.
300 WORDS FOR HELP WITH PSYCHOLOGY HOMEWORK:

The Z-score is a method for calculating the likelihood of a score. This may be knowing how low or high to score on an exam in order to pass or fail. Knowing the mean and standard deviation makes it possible to convert to a z table and calculate the percentage of a score. Knowing the mean and score only allows for one score and average to be applied to all of the data. Knowing your exam result and the average of all previous exams will not give you the score you want or need to pass. The z-score might be used to predict the grade needed to pass if a student was failing and had two more tests coming up.

A z score of 0 equals a score at the mean. A z score of +1.0 corresponds to a score 1 SD above the mean. A z score of -1.0 corresponds to a score 1 below the mean” (Week3 Lecture 1).

Using the information below on the provided charts as an example

Rounding to a mean of 85 and a standard deviation of 6. On a normal distribution bell curve, the mean of 85 is in the middle, or 50% of the total. You would use the mean and SD to translate to a z score to reach the top 25%. A z score is a table that contains the stated criteria. To accommodate the top 25%, you’ll need to achieve a percentage of at least 75%. On a Z table, to be precise. The result of 68 is 75.17, which is equal to the required 75 percent. That’s something I’d take. 68×6+85=89.08 multiply by SD and add the mean According to the data below, Crystal and Skylar are in the top 25% of their class.

IN 300 WORDS OR LESS, RESPOND:

A z-principal score’s purpose is to describe the precise placement of a score within a distribution. By converting each X value into a signed number (+or-), the z-score achieves this purpose. The indication indicates whether the score is higher (+) or lower (-). (-) The difference between the score and the mean in terms of standard deviations is given by the mean and the number.

To gain further information about how a person fared on a test, the z-score is required. Even if you only have the mean and the value of the score, you’ll still need the standard deviation to calculate the right z-score.

Students’ Z-Scores on standardized tests

S1 -0.360624459 S1 175 -0.360624459 S1 175 -0.36062

S2 1.831406566 1.831406566 1.831406566 1.831406566 1.83140

S3 150 -2.128391415 S3 150 -2.128391415 S3 150 -2.128

S4 -1.067731241 S4 165 -1.067731241 S4 165 -1.06773

180 -0.007071068 S5 180 -0.007071068 S5 180 -0.0070710

S6 210 2.114249279 210 2.114249279 210 2.114249279 210

1.407142497 S7 200 S7 200 S7 200 S7 200 S7 200 S7 200 S

S8 190 0.700035715 S8 190 0.700035715 S8 190 0.70003

S9 170 -0.71417785 -0.71417785 -0.71417785 -0.714177

S10 155 -1.774838024 S10 155 -1.774838024 S10 155 -1.

The total number of points is 180.1.

Scores with a standard deviation of 14.14213562

When you obtain a z-score, you’re getting a standardized score that tells you a little bit more about the average of the ten pupils.

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